0.6x^2+3.6x+0.6=(3+0.6x)(1+x)

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Solution for 0.6x^2+3.6x+0.6=(3+0.6x)(1+x) equation: 



0.6x^2+3.6x+0.6=(3+0.6x)(1+x)

We move all terms to the left:

0.6x^2+3.6x+0.6-((3+0.6x)(1+x))=0

We add all the numbers together, and all the variables

0.6x^2+3.6x-((0.6x+3)(x+1))+0.6=0

We multiply parentheses ..

0.6x^2-((+0x^2+0x+3x+3))+3.6x+0.6=0



We calculate terms in parentheses: -((+0x^2+0x+3x+3)), so:

(+0x^2+0x+3x+3)

We get rid of parentheses

0x^2+0x+3x+3

We add all the numbers together, and all the variables

x^2+4x+3

Back to the equation:

-(x^2+4x+3)



We add all the numbers together, and all the variables

0.6x^2+3.6x-(x^2+4x+3)+0.6=0

We get rid of parentheses

0.6x^2-x^2+3.6x-4x-3+0.6=0

We add all the numbers together, and all the variables

-0.4x^2-0.4x-2.4=0

a = -0.4; b = -0.4; c = -2.4;
Δ = b2-4ac
Δ = -0.42-4·(-0.4)·(-2.4)
Δ = -3.68
Delta is less than zero, so there is no solution for the equation

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